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Author Topic: Q1-T0801  (Read 4948 times)

Victor Ivrii

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Q1-T0801
« on: January 25, 2018, 08:16:13 AM »
Find the general solution of the given equation:
\begin{equation*}
xy' = (1 - y^2)^{1/2}.
\end{equation*}
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Junya Zhang

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Re: Q1-T0801
« Reply #1 on: January 25, 2018, 08:58:51 AM »
« Last Edit: January 25, 2018, 09:20:33 AM by Junya Zhang »
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Tiange Gao

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Re: Q1-T0801
« Reply #2 on: January 25, 2018, 03:51:40 PM »
Should |y| be less than 1?
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