problem 3

[Aida Razi]

Question 3 part a: p has to be= ((y-x+2kαt) / (√ 2kt)) instead of ((y-x+2kαt) / (√ 4kt)) in Peishan's solution.

[Peishan Wang]

I think it doesn't matter. If you use the error function (the first attachment) provided by our professor, then you let p = ((y-x+2kαt) / (√ 2kt)). If you use the other form (the second attachment) which is used in the textbook, then you let p = ((y-x+2kαt) / (√ 4kt)).

And in another post, http://forum.math.toronto.edu/index.php?topic=49.0 Julong has shown that these two forms are actually equivalent.

Professor can you provide some feedback to the posted solutions? It seems that you ignored this post completely. Thanks.

[Victor Ivrii]

I think it doesn't matter. If you use the error function (the first attachment) provided by our professor, then you let p = ((y-x+2kαt) / (√ 2kt)). If you use the other form (the second attachment) which is used in the textbook, then you let p = ((y-x+2kαt) / (√ 4kt)).

And in another post, http://forum.math.toronto.edu/index.php?topic=49.0 Julong has shown that these two forms are actually equivalent.

Professor can you provide some feedback to the posted solutions? It seems that you ignored this post completely. Thanks.

You are correct.

PS I am not on 24/7 shift

[Aida Razi]

Solution to question3 part b is attached!

[Fanxun Zeng]

Thanks Aida for posting Part b in December. As there is still NO solution posted for Part d yet, I spent 1 hour to write part d and post attached same 2 images, first by camera, second by scan.

Thanks professor. Here I used error function in the textbook, instead of that given in the homework, but yes they are same. In part d, I got limit u(x,t)=1 for Neumann condition.