TUT5101 QUIZ2

[Yiheng Bian]

Question:
$$
h(z)=\frac{Log(z)}{z}
$$
We know when
$$
 z \rightarrow \infty
$$
$$
Log(z) \rightarrow \infty
$$
So we can use L'Hopital rules and get
$$
\frac{1}{z}
$$
So
$$
\text{limit is zero}
$$

[Victor Ivrii]

Wrong reasoning

[Yiheng Bian]

Sorry sir, , could you point it out?

[Victor Ivrii]

You cannot use LH out of the box for complex variables. You need to consider $z=re^{i\theta}$ and consider $\bigl|\dfrac{\operatorname{Log}(z)}{z}\bigr|$ ...

[Yiheng Bian]

Ok, I got it. Thank you sir