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If the Wronskian W of f and g is $3e^{4t}$, and if $f(t)=e^{2t}$, find g(t)
Solution: We calculate the Wronskian of f and g:
$W =
\begin{vmatrix}
f(t) & g(t) \\
f'(t) & g'(t) \\
\end{vmatrix}
=
\begin{vmatrix}
e^{2t} & g(t) \\
2e^{2t} & g'(t) \\
\end{vmatrix} $
= $e^{2t}g'(t)-2e^{2t}g(t)=3e^{4t}$ \newline
$e^{2t}g'(t)-2e^{2t}g(t)=3e^{4t}$ \newline
