quiz3 0501

[Hongling Liu]

    y‘’ - 2y’ - 2y = 0
    Solution:
    r^2 - 2r - 2= 0
    r1 = 1 +√3
    r2 = 1- √3
    y = C1⋅e^(1+√3)⋅t + C2⋅e^(1-√3)⋅t