TT2A-P3

[Victor Ivrii]

(a) Find the general solution of
$$
\mathbf{x}'=\begin{pmatrix} \ 4 & \ 1\\
-3 &0\end{pmatrix}\mathbf{x}.$$

(b) Sketch corresponding trajectories. Describe the picture (stable/unstable, node, focus, center, saddle).

(c) Solve
$$
\mathbf{x}'=\begin{pmatrix}\hphantom{-}4 & \ 1\\
-3 &0\end{pmatrix}\mathbf{x} +
\begin{pmatrix} \hphantom{-}\frac{4e^{4t}}{e^t+1} \\
-\frac{4e^{4t}}{e^t+1}\end{pmatrix},\qquad
\mathbf{x}(0)=\begin{pmatrix}-1 \\
\hphantom{-}3\end{pmatrix}.
$$

[Mallory Schneider]

Part a) and b)

[Michael Poon]

I think you could also characterise the phase portrait as a node? (unstable node)

[Mallory Schneider]

Part C

[Victor Ivrii]

I think you could also characterise the phase portrait as a node? (unstable node)

Indeed


Computer generated