Q2 TUT 0102

[Victor Ivrii]

Find all points of continuity of the given function:
\begin{equation*}(z)=(1-|z|^2)^{-3}.
\end{equation*}

[Ye Jin]

Since\begin{equation*} |z|^2=x^2+y^2\end{equation*},
then  \begin{equation*}g(z)= \frac{1}{[1-(x^2+y^2)]^3}\end{equation*}   
Hence, g(z) is not continuous at all points of circle \begin{equation*}x^2+y^2=1\end{equation*}