Author Topic: More on inversion  (Read 2812 times)

Zhekai Pang

  • Newbie
  • *
  • Posts: 3
  • Karma: 0
    • View Profile
More on inversion
« on: September 15, 2020, 07:47:28 PM »
In addition to the last slide of today's lecture.
« Last Edit: September 15, 2020, 07:51:06 PM by Zhekai Pang »

RunboZhang

  • Sr. Member
  • ****
  • Posts: 51
  • Karma: 0
    • View Profile
Re: More on inversion
« Reply #1 on: September 16, 2020, 03:46:45 PM »
Hi Zhekai, thank you for your sharing. I have two questions regarding your notes. Firstly, how did you derive A prime and B prime? Did you convert A and B in polar form and calculate their inverse, and then represent on the graph? Secondly, how did you know that z*zbar = r^2?

Victor Ivrii

  • Administrator
  • Elder Member
  • *****
  • Posts: 2607
  • Karma: 0
    • View Profile
    • Personal website of Victor Ivrii
Re: More on inversion
« Reply #2 on: September 17, 2020, 01:58:27 PM »
Note that our inversion differs from geometric one $\vec{z}\to \frac{\vec{x}}{|\vec{x}|^2}$. It includes a mirror-reflection. See handout (I made a picture based on your example, corrected. Thanks a lot)