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Quiz-2 / Re: Q2-T5101
« on: February 02, 2018, 02:59:04 PM »
x2y3/xy3 + x(1 + y2)/xy3y' = 0
x + (y−3 + y−1)y' = 0
∫M dx = 1/2x2 + g(y)
g(y) = ∫y−3 + 1/ydy = -1/2y−2 + ln(y)
The solution is:
1/2x2 − 1/2y2 + ln(y) = C
x + (y−3 + y−1)y' = 0
∫M dx = 1/2x2 + g(y)
g(y) = ∫y−3 + 1/ydy = -1/2y−2 + ln(y)
The solution is:
1/2x2 − 1/2y2 + ln(y) = C