1
Chapter 4 / 4.2 Example 4(periodic)
« on: November 02, 2016, 02:10:55 PM »
$$X^{''} + \lambda X = 0$$
with condition $$X(0) = X(l), X^{'}(0) = X^{'}(l)$$
how to get the answer $$\lambda_{2n-1} = \lambda_{2n} = (\frac{n\pi}{2l})^{2}$$ and the corresponding eigenfunctions?
with condition $$X(0) = X(l), X^{'}(0) = X^{'}(l)$$
how to get the answer $$\lambda_{2n-1} = \lambda_{2n} = (\frac{n\pi}{2l})^{2}$$ and the corresponding eigenfunctions?