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Quiz-5 / TUT0301 Quiz5
« on: November 10, 2019, 04:03:12 PM »
Question:
(1−t)y′′ +ty′ −y=2(t−1)2e−t, 0<t<1
y1(t) = e^t, y2(t) = t
(1−t)y′′ +ty′ −y=2(t−1)2e−t, 0<t<1
y1(t) = e^t, y2(t) = t
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Quiz-3 / TUT0301 Quiz3
« on: October 11, 2019, 05:07:19 PM »
Question: 2y'' +y' - 4y=0, y(0)=1,y'(0)=0
Pages: [1]